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409=-0.5x^2+36x-185
We move all terms to the left:
409-(-0.5x^2+36x-185)=0
We get rid of parentheses
0.5x^2-36x+185+409=0
We add all the numbers together, and all the variables
0.5x^2-36x+594=0
a = 0.5; b = -36; c = +594;
Δ = b2-4ac
Δ = -362-4·0.5·594
Δ = 108
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{108}=\sqrt{36*3}=\sqrt{36}*\sqrt{3}=6\sqrt{3}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-36)-6\sqrt{3}}{2*0.5}=\frac{36-6\sqrt{3}}{1} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-36)+6\sqrt{3}}{2*0.5}=\frac{36+6\sqrt{3}}{1} $
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